Composition Series/Examples/Dihedral Group D6

From ProofWiki
Jump to navigation Jump to search

Example of Composition Series

There are $3$ composition series of the dihedral group $D_6$, up to isomorphism:

$\set e \lhd C_3 \lhd C_6 \lhd D_6$
$\set e \lhd C_2 \lhd C_6 \lhd D_6$
$\set e \lhd C_3 \lhd D_3 \lhd D_6$

where $C_n$ denotes the cyclic group of order $n$.


Proof

Let $D_6$ be defined as by Group Presentation of Dihedral Group:

$D_6 = \gen {\alpha, \beta: \alpha^6 = \beta^2 = e, \beta \alpha \beta = \alpha^{−1} }$


From Subgroups of Symmetry Group of Regular Hexagon, $D_6$ has $3$ subgroups of index $2$:

$\set {e, \alpha, \alpha^2, \alpha^3, \alpha^4, \alpha^5}$
$\set {e, \alpha^2, \alpha^4, \beta, \alpha^2 \beta, \alpha^4 \beta}$
$\set {e, \alpha^2, \alpha^4, \alpha \beta, \alpha^3 \beta, \alpha^5 \beta}$


We have that:

$\set {e, \alpha, \alpha^2, \alpha^3, \alpha^4, \alpha^5} = \gen \alpha = C_6$

and:

$\set {e, \alpha^2, \alpha^4, \beta, \alpha^2 \beta, \alpha^4 \beta} = \gen {\alpha^2, \beta: \paren {\alpha^2}^3 = \beta^2 = e, \beta \alpha^2 \beta = \paren {\alpha^2}^{−1} } = D_3$

and:

$\set {e, \alpha^2, \alpha^4, \alpha \beta, \alpha^3 \beta, \alpha^5 \beta} = \gen {\alpha^2, \alpha \beta: \paren {\alpha^2}^3 = \paren {\alpha \beta}^2 = e, \paren {\alpha \beta} \alpha^2 \paren {\alpha \beta} = \paren {\alpha^2}^{−1} } = D_3$


By Subgroup of Index 2 is Normal, all these are normal.

Thus we have so far:

$\set e \lhd \cdots \lhd C_6 \lhd D_6$
$\set e \lhd \cdots \lhd D_3 \lhd D_6$


We have from Cyclic Group is Abelian and Subgroup of Abelian Group is Normal that all subgroups of $C_6$ are normal in $C_6$.

This leads directly to the composition series:

$\set e \lhd C_3 \lhd C_6 \lhd D_6$
$\set e \lhd C_2 \lhd C_6 \lhd D_6$


We have that $D_3$ is isomorphic to $S_3$, the symmetric group on $3$ letters.

From Normal Subgroups of $S_3$, the only normal subgroup of $D_3$ is $C_3$.

This leads to the composition series:

$\set e \lhd C_3 \lhd D_3 \lhd D_6$


As there are no more normal subgroups of $D_3$, there are no further composition series of $D_6$.

$\blacksquare$


Sources