Consecutive Primes of form 4n+1

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Theorem

The sequence of $16$ consecutive prime numbers beginning from $207 \, 622 \, 273$ are all of the form $4 n + 1$.


Proof

\(\text {(1)}: \quad\) \(\ds 207 \, 622 \, 273\) \(=\) \(\ds 4 \times 51 \, 905 \, 568 + 1\) and is the $11 \, 477 \, 482$nd prime
\(\text {(2)}: \quad\) \(\ds 207 \, 622 \, 297\) \(=\) \(\ds 4 \times 51 \, 905 \, 574 + 1\) and is the $11 \, 477 \, 483$rd prime
\(\text {(3)}: \quad\) \(\ds 207 \, 622 \, 301\) \(=\) \(\ds 4 \times 51 \, 905 \, 575 + 1\) and is the $11 \, 477 \, 484$th prime
\(\text {(4)}: \quad\) \(\ds 207 \, 622 \, 313\) \(=\) \(\ds 4 \times 51 \, 905 \, 578 + 1\) and is the $11 \, 477 \, 485$th prime
\(\text {(5)}: \quad\) \(\ds 207 \, 622 \, 321\) \(=\) \(\ds 4 \times 51 \, 905 \, 580 + 1\) and is the $11 \, 477 \, 486$th prime
\(\text {(6)}: \quad\) \(\ds 207 \, 622 \, 381\) \(=\) \(\ds 4 \times 51 \, 905 \, 595 + 1\) and is the $11 \, 477 \, 487$th prime
\(\text {(7)}: \quad\) \(\ds 207 \, 622 \, 409\) \(=\) \(\ds 4 \times 51 \, 905 \, 602 + 1\) and is the $11 \, 477 \, 488$th prime
\(\text {(8)}: \quad\) \(\ds 207 \, 622 \, 417\) \(=\) \(\ds 4 \times 51 \, 905 \, 604 + 1\) and is the $11 \, 477 \, 489$th prime
\(\text {(9)}: \quad\) \(\ds 207 \, 622 \, 421\) \(=\) \(\ds 4 \times 51 \, 905 \, 605 + 1\) and is the $11 \, 477 \, 490$th prime
\(\text {(10)}: \quad\) \(\ds 207 \, 622 \, 489\) \(=\) \(\ds 4 \times 51 \, 905 \, 622 + 1\) and is the $11 \, 477 \, 491$st prime
\(\text {(11)}: \quad\) \(\ds 207 \, 622 \, 501\) \(=\) \(\ds 4 \times 51 \, 905 \, 625 + 1\) and is the $11 \, 477 \, 492$nd prime
\(\text {(12)}: \quad\) \(\ds 207 \, 622 \, 517\) \(=\) \(\ds 4 \times 51 \, 905 \, 629 + 1\) and is the $11 \, 477 \, 493$rd prime
\(\text {(13)}: \quad\) \(\ds 207 \, 622 \, 537\) \(=\) \(\ds 4 \times 51 \, 905 \, 634 + 1\) and is the $11 \, 477 \, 494$th prime
\(\text {(14)}: \quad\) \(\ds 207 \, 622 \, 549\) \(=\) \(\ds 4 \times 51 \, 905 \, 637 + 1\) and is the $11 \, 477 \, 495$th prime
\(\text {(15)}: \quad\) \(\ds 207 \, 622 \, 553\) \(=\) \(\ds 4 \times 51 \, 905 \, 638 + 1\) and is the $11 \, 477 \, 496$th prime
\(\text {(16)}: \quad\) \(\ds 207 \, 622 \, 561\) \(=\) \(\ds 4 \times 51 \, 905 \, 640 + 1\) and is the $11 \, 477 \, 497$th prime


Note that the $11 \, 477 \, 481$st prime:

$207 \, 622 \, 271 = 4 \times 51 \, 905 \, 568 - 1$

and the $11 \, 477 \, 498$th prime:

$207 \, 622 \, 567 = 4 \times 51 \, 905 \, 642 - 1$

and so are not of the form $4 n + 1$.

$\blacksquare$


Historical Note

This result is reported by David Wells in his Curious and Interesting Numbers, 2nd ed. of $1997$ as the work of Stephane Vandemergel, but details are lacking.


Sources