Construction of Components of Side of Rational plus Medial Area
Theorem
In the words of Euclid:
- To find two straight lines incommensurable in square which make the sum of the squares on them medial but the rectangle contained by them rational.
(The Elements: Book $\text{X}$: Proposition $34$)
Proof
Let $AB$ and $BC$ be medial straight lines which are commensurable in square only such that:
- $AB^2 = BC^2 + \rho^2$
such that $\rho$ is incommensurable in length with $AB$.
Let the semicircle $ADB$ be drawn with $AB$ as the diameter.
Let $BC$ be bisected at $E$.
From Construction of Parallelogram Equal to Given Figure Exceeding a Parallelogram:
Let a parallelogram be applied to $AB$ equal to the square on either of $BE$ or $EC$, and deficient by a square.
Let this parallelogram be the rectangle contained by $AF$ and $FB$.
- $AF$ is incommensurable in length with $FB$.
Let $FD$ be drawn perpendicular to $AB$.
Join $AD$ and $DB$.
We have that $AF$ is incommensurable in length with $FB$.
So from Proposition $11$ of Book $\text{X} $: Commensurability of Elements of Proportional Magnitudes:
- $BA \cdot AF$ is incommensurable with $AB \cdot BF$.
From Lemma to Proposition $33$ of Book $\text{X} $: Construction of Components of Major:
- $BA \cdot AF = AD^2$
and:
- $AB \cdot BF = DB^2$
Therefore $AD^2$ and $DB^2$ are incommensurable.
As $AB$ is medial, it follows by definition that $AB^2$ is a medial area.
From Pythagoras's Theorem:
- $AB^2 = \left({AD + DB}\right)^2$
Thus $\left({AD + DB}\right)^2$ is also a medial area.
Therefore $AF + FB$ is medial.
As $BC = 2 DF$:
- $AB \cdot BC = 2 AB \cdot FD$
But $AB \cdot BC$ is a rational area.
Therefore from Proposition $6$ of Book $\text{X} $: Magnitudes with Rational Ratio are Commensurable:
- $AB \cdot FD$ is a rational area.
But from Lemma to Proposition $33$ of Book $\text{X} $: Construction of Components of Major:
- $AB \cdot FD = AD \cdot DB$
Thus $AD \cdot DB$ is a rational area.
Therefore we have found two straight lines which are incommensurable in square whose sum of squares is medial, but such that the rectangle contained by them is rational.
$\blacksquare$
Also see
Historical Note
This proof is Proposition $34$ of Book $\text{X}$ of Euclid's The Elements.
Sources
- 1926: Sir Thomas L. Heath: Euclid: The Thirteen Books of The Elements: Volume 3 (2nd ed.) ... (previous) ... (next): Book $\text{X}$. Propositions