Convergent Complex Series/Examples/((2+3i) over (4+i))^n
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Example of Convergent Complex Series
The series $\ds \sum_{n \mathop = 1}^\infty a_n$, where:
- $a_n = \paren {\dfrac {2 + 3 i} {4 + i} }^n$
is convergent.
Proof
\(\ds \cmod {\dfrac {2 + 3 i} {4 + i} }\) | \(=\) | \(\ds \cmod {\dfrac {\paren {2 + 3 i} \paren {4 - i} } {\paren {4 + i} \paren {4 - i} } }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \cmod {\dfrac {8 + 10 i + 3} {4^2 + 1^2} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \cmod {\dfrac {11 + 10 i} {17} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \sqrt {\dfrac {11^2 + 10^2} {17^2} }\) | Definition of Complex Modulus | |||||||||||
\(\ds \) | \(=\) | \(\ds \sqrt {\dfrac {221} {289} }\) | Definition of Complex Modulus | |||||||||||
\(\ds \) | \(<\) | \(\ds 1\) |
Thus $\ds \sum_{n \mathop = 1}^\infty \paren {\dfrac {2 + 3 i} {4 + i} }^n$ is absolutely convergent by Sum of Infinite Geometric Sequence.
The result follows from Absolutely Convergent Series is Convergent: Complex Numbers.
$\blacksquare$
Sources
- 1960: Walter Ledermann: Complex Numbers ... (previous) ... (next): $\S 4$. Elementary Functions of a Complex Variable: Exercise $2 \ \text {(iv)}$