Converse of Conditional is Inverse of Contrapositive
Jump to navigation
Jump to search
Theorem
Let $p \implies q$ be a conditional.
Then the converse of $p \implies q$ is the inverse of its contrapositive.
Proof
The converse of $p \implies q$ is:
- $q \implies p$
The contrapositive of $p \implies q$ is:
- $\neg q \implies \neg p$
The inverse of $\neg q \implies \neg p$ is:
- $\neg \neg q \implies \neg \neg p$
By Double Negation, the two are seen to be equal.
$\blacksquare$