Cotangent of 240 Degrees

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Theorem

$\cot 240^\circ = \cot \dfrac {4 \pi} 3 = \dfrac {\sqrt 3} 3$

where $\cot$ denotes cotangent.


Proof

\(\ds \cot 240^\circ\) \(=\) \(\ds \cot \left({360^\circ - 120^\circ}\right)\)
\(\ds \) \(=\) \(\ds -\cot 120^\circ\) Cotangent of Conjugate Angle
\(\ds \) \(=\) \(\ds \frac {\sqrt 3} 3\) Cotangent of 120 Degrees

$\blacksquare$


Sources