Countable Open Covers Condition for Separated Sets/Lemma 2
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Theorem
Let $T = \struct {S, \tau}$ be a topological space.
Let $\family {U_n}_{n \mathop \in \N}$ be a countable family of open sets.
Let $\family {V_n}_{n \mathop \in \N}$ be a countable family of open sets.
For each $n \in \N$, let:
- ${U_n}' = U_n \setminus \paren {\ds \bigcup_{p \mathop \le n} {V_p}^-}$
For each $n \in \N$, let:
- ${V_n}' = V_n \setminus \paren {\ds \bigcup_{p \mathop \le n} {U_p}^-}$
Let:
- $U = \ds \bigcup_{n \mathop \in \N} {U_n}'$
and
- $V = \ds \bigcup_{n \mathop \in \N} {V_n}'$
Then:
- $U$ and $V$ are open in $T$.
Proof
By Open Set Axiom $\paren {\text O 2 }$: Pairwise Intersection of Open Sets, it is sufficient to show that:
- $\forall n \in \N : {U_n}', {V_n}' \in \tau$
Let $n \in \N$.
We have:
\(\ds {U_n}'\) | \(=\) | \(\ds U_n \setminus \paren {\ds \bigcup_{p \mathop \le n} {V_p}^-}\) | Definition of ${U_n}'$ | |||||||||||
\(\ds \) | \(=\) | \(\ds U_n \cap \relcomp S {\bigcup_{p \mathop \le n} {V_p}^-}\) | Set Difference as Intersection with Relative Complement | |||||||||||
\(\ds \) | \(=\) | \(\ds U_n \cap \paren{ \bigcap_{p \mathop \le n} \relcomp S { {V_p}^-} }\) | De Morgan's laws |
From Topological Closure is Closed:
- ${V_p}^-$ is a closed set.
By definition of closed set:
- $\relcomp S {V_p^-}$ is an open set.
Hence:
- ${U_n}'$ is the finite intersection of open sets.
By Open Set Axiom $\paren {\text O 3 }$: Underlying Set is Element of Topology:
- ${U_n}'$ is an open set.
Similarly:
- ${V_n}'$ is an open set.
The result follows from Open Set Axiom $\paren {\text O 2 }$: Pairwise Intersection of Open Sets.
$\blacksquare$