De Morgan's Laws (Logic)/Conjunction/Formulation 1/Forward Implication

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Theorem

$p \land q \vdash \neg \left({\neg p \lor \neg q}\right)$


Proof

By the tableau method of natural deduction:

$p \land q \vdash \neg \left({\neg p \lor \neg q}\right)$
Line Pool Formula Rule Depends upon Notes
1 1 $p \land q$ Premise (None)
2 1 $p$ Rule of Simplification: $\land \EE_1$ 1
3 1 $q$ Rule of Simplification: $\land \EE_2$ 1
4 4 $\neg p \lor \neg q$ Assumption (None)
5 5 $\neg p$ Assumption (None)
6 1, 5 $\bot$ Principle of Non-Contradiction: $\neg \EE$ 2, 5
7 7 $\neg q$ Assumption (None)
8 1, 7 $\bot$ Principle of Non-Contradiction: $\neg \EE$ 3, 7
9 1, 4 $\bot$ Proof by Cases: $\text{PBC}$ 4, 5 – 6, 7 – 8 Assumptions 5 and 7 have been discharged
10 1 $\neg \left({\neg p \lor \neg q}\right)$ Proof by Contradiction: $\neg \II$ 4 – 9 Assumption 4 has been discharged

$\blacksquare$


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