Definite Integral from 0 to 1 of Logarithm of x over One minus x
Jump to navigation
Jump to search
This article has been identified as a candidate for Featured Proof status. If you do not believe that this proof is worthy of being a Featured Proof, please state your reasons on the talk page. To discuss this page in more detail, feel free to use the talk page. |
Theorem
- $\ds \int_0^1 \frac {\ln x} {1 - x} \rd x = -\frac {\pi^2} 6$
Proof
\(\ds \int_0^1 \frac {\ln x} {1 - x} \rd x\) | \(=\) | \(\ds \int_0^1 \ln x \paren {\sum_{n \mathop = 0}^\infty x^n} \rd x\) | Sum of Infinite Geometric Sequence | |||||||||||
\(\ds \) | \(=\) | \(\ds \sum_{n \mathop = 0}^\infty \paren {\int_0^1 x^n \ln x \rd x}\) | Fubini's Theorem | |||||||||||
\(\ds \) | \(=\) | \(\ds -\sum_{n \mathop = 0}^\infty \frac {\map \Gamma 2} {\paren {n + 1}^2}\) | Definite Integral from $0$ to $1$ of $x^m \paren {\ln x}^n$: $n \gets 1$, $m \gets n$ | |||||||||||
\(\ds \) | \(=\) | \(\ds -\sum_{n \mathop = 1}^\infty \frac 1 {n^2}\) | shifting the index, Gamma Function Extends Factorial | |||||||||||
\(\ds \) | \(=\) | \(\ds -\frac {\pi^2} 6\) | Basel Problem |
$\blacksquare$
Also see
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 15$: Definite Integrals involving Logarithmic Functions: $15.92$