Definite Integral to Infinity of Reciprocal of Exponential of x minus One minus Exponential of -x over x
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Theorem
- $\ds \int_0^\infty \paren {\frac 1 {e^x - 1} - \frac {e^{-x} } x} \rd x = \gamma$
where $\gamma$ denotes the Euler-Mascheroni constant.
Proof
\(\ds \gamma\) | \(=\) | \(\ds \lim_{n \mathop \to \infty} \paren {\sum_{k \mathop = 1}^n \frac 1 k - \ln n}\) | Definition of Euler-Mascheroni Constant | |||||||||||
\(\ds \) | \(=\) | \(\ds \lim_{n \mathop \to \infty} \paren {\sum_{k \mathop = 1}^n \paren {\int_0^1 x^{k - 1} \rd x } + \int_0^1 \frac {1 - x^{n - 1} } {\ln x} \rd x}\) | Primitive of Power, Definite Integral from $0$ to $1$ of $\dfrac {x^m - x^n} {\ln x}$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \lim_{n \mathop \to \infty} \paren {\int_0^1 \paren {\sum_{k = 1}^n x^{k - 1} } \rd x + \int_0^1 \frac {1 - x^{n - 1} } {\ln x} \rd x}\) | Linear Combination of Definite Integrals | |||||||||||
\(\ds \) | \(=\) | \(\ds \lim_{n \mathop \to \infty} \paren {\int_0^1 \paren {\frac {1 - x^n} {1 - x} + \frac {1 - x^{n - 1} } {\ln x} } \rd x}\) | Sum of Infinite Geometric Sequence | |||||||||||
\(\ds \) | \(=\) | \(\ds \int_0^1 \lim_{n \mathop \to \infty} \paren {\frac {1 - x^n} {1 - x} + \frac {1 - x^{n - 1} } {\ln x} } \rd x\) | Lebesgue's Dominated Convergence Theorem | |||||||||||
\(\ds \) | \(=\) | \(\ds \int_0^1 \paren {\frac 1 {1 - x} + \frac 1 {\ln x} } \rd x\) | Sequence of Powers of Number less than One |
Let:
- $x = e^{-t}$
- $\dfrac {\d x} {\d t} = -e^{-t}$
By Exponential of Zero, we have:
- as $x \to 1$, $t \to 0$.
By Exponential Tends to Zero and Infinity, we have:
- as $x \to 0$, $t \to \infty$.
We therefore have:
\(\ds \int_0^1 \paren {\frac 1 {1 - x} + \frac 1 {\ln x} } \rd x\) | \(=\) | \(\ds -\int_\infty^0 e^{-t} \paren {\frac 1 {1 - e^{-t} } + \frac 1 {\map \ln {e^{-t} } } } \rd t\) | substituting $x = e^{-t}$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \int_0^\infty e^{-t} \paren {\frac {e^t} {e^t - 1} - \frac 1 t} \rd t\) | Reversal of Limits of Definite Integral, Definition of Natural Logarithm | |||||||||||
\(\ds \) | \(=\) | \(\ds \int_0^\infty \paren {\frac 1 {e^t - 1} - \frac {e^{-t} } t} \rd t\) |
$\blacksquare$
Also see
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 15$: Definite Integrals involving Exponential Functions: $15.86$