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Let $\RR \subseteq S \times T$ be a relation.

Let $\RR^{-1} \subseteq T \times S$ be the inverse relation to $\RR$, defined as:

$\RR^{-1} = \set {\tuple {t, s}: \tuple {s, t} \in \RR}$

Let $Y \subseteq T$.

The preimage of $Y$ under $\RR$ is defined as:

$\RR^{-1} \sqbrk Y := \set {s \in S: \exists t \in Y: \tuple {s, t} \in \RR}$

That is, the preimage of $Y$ under $\RR$ is the image of $Y$ under $\RR^{-1}$:

$\RR^{-1} \sqbrk Y := \set {s \in S: \exists t \in Y: \tuple {t, s} \in \RR^{-1} }$

If no element of $Y$ has a preimage, then $\RR^{-1} \sqbrk Y = \O$.

Preimage of Subset as Element of Inverse Image Mapping

The preimage of $Y$ under $\RR$ can be seen to be an element of the codomain of the inverse image mapping $\RR^\gets: \powerset T \to \powerset S$ of $\RR$:

$\forall Y \in \powerset T: \map {\RR^\gets} Y := \set {s \in S: \exists t \in Y: \tuple {s, t} \in \RR}$


$\forall Y \subseteq T: \RR^{-1} \sqbrk Y = \map {\RR^\gets} Y$

and so the preimage of $Y$ under $\RR$ is also seen referred to as the inverse image of $Y$ under $\RR$.

Both approaches to this concept are used in $\mathsf{Pr} \infty \mathsf{fWiki}$.

Also known as

The preimage of $Y$ is also known as the inverse image of $Y$.

The term preimage set is also seen.

Also see

Special Cases


Related Concepts