Definition:Preimage of Subset under Mapping/Definition 1
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Definition
Let $f: S \to T$ be a mapping.
Let $f^{-1} \subseteq T \times S$ be the inverse of $f$, defined as:
- $f^{-1} = \set {\tuple {t, s}: \map f s = t}$
Let $Y \subseteq T$.
The preimage of $Y$ under $f$ is defined as:
- $f^{-1} \sqbrk Y := \set {s \in S: \exists t \in Y: \map f s = t}$
That is, the preimage of $Y$ under $f$ is the image of $Y$ under $f^{-1}$, where $f^{-1}$ can be considered as a relation.
If no element of $Y$ has a preimage, then $f^{-1} \sqbrk Y = \O$.
Also known as
Some sources use counter image or inverse image instead of preimage.
Some sources use the notation $\map {f^\gets} Y$ for $f^{-1} \sqbrk Y$.
Also see
Sources
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- For a video presentation of the contents of this page, visit the Khan Academy.