Derivative of Cosine Function/Proof 4

From ProofWiki
Jump to navigation Jump to search

Theorem

$\map {\dfrac \d {\d x} } {\cos x} = -\sin x$


Proof

\(\ds \map {\frac \d {\d x} } {\cos x}\) \(=\) \(\ds \lim_{h \mathop \to 0} \frac {\map \cos {x + h} - \cos x} h\) Definition of Derivative of Real Function at Point
\(\ds \) \(=\) \(\ds \lim_{h \mathop \to 0} \frac {\map \cos {\paren {x + \frac h 2} + \frac h 2} - \map \cos {\paren {x + \frac h 2} - \frac h 2} } h\)
\(\ds \) \(=\) \(\ds \lim_{h \mathop \to 0} \frac {-2 \map \sin {x + \frac h 2} \map \sin {\frac h 2} } h\) Werner Formula for Sine by Sine
\(\ds \) \(=\) \(\ds -\lim_{h \mathop \to 0} \map \sin {x + \frac h 2} \lim_{h \mathop \to 0} \frac {\map \sin {\frac h 2} } {\frac h 2}\) Multiple Rule for Limits of Real Functions and Product Rule for Limits of Real Functions
\(\ds \) \(=\) \(\ds -\sin x \times 1\) Real Sine Function is Continuous and Limit of $\dfrac {\sin x} x$ at Zero
\(\ds \) \(=\) \(\ds -\sin x\)

$\blacksquare$


Sources