Divisor Count of 108/Mistake

Source Work

1997: David Wells: Curious and Interesting Numbers (2nd ed.):

The Dictionary

$108$

Mistake

The number of its factors is also a cube: $8$.

Notwithstanding the fact that the also is redundant, as $108$ is not actually a cube itself for $8$ to be also to, the count of the factors of $108$ is in fact $12$, not $8$.

This is shown at $\sigma_0$ of $108$.

It is probable that this is a typesetting error, as in the following paragraph it is pointed out that $\map {\sigma_1} {110}$ is a cube.

We also have from $\sigma_0$ of $110$ that $\map {\sigma_0} {110}$ is indeed equal to $8$.

Sources

• 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $108$