Equation of Straight Line in Plane/Two-Point Form/Parametric Form
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Theorem
Let $\LL$ be a straight line embedded in a cartesian plane, given in two-point form as:
- $\dfrac {x - x_1} {x_2 - x_1} = \dfrac {y - y_1} {y_2 - y_1}$
Then $\LL$ can be expressed by the parametric equations:
- $\begin {cases} x = x_1 + t \paren {x_2 - x_1} \\ y = y_1 + t \paren {y_2 - y_1} \end {cases}$
Proof
Let $P = \tuple {x, y}$ be an arbitrary point on $\LL$.
Let $t = \dfrac {x - x_1} {x_2 - x_1} = \dfrac {y - y_1} {y_2 - y_1}$.
We then have:
\(\ds t\) | \(=\) | \(\ds \dfrac {x - x_1} {x_2 - x_1}\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds x - x_1\) | \(=\) | \(\ds t \paren {x_2 - x_1}\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds x\) | \(=\) | \(\ds x_1 + t \paren {x_2 - x_1}\) |
\(\ds t\) | \(=\) | \(\ds \dfrac {y - y_1} {y_2 - y_1}\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds y - y_1\) | \(=\) | \(\ds t \paren {y_2 - y_1}\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds y\) | \(=\) | \(\ds y_1 + t \paren {y_2 - y_1}\) |
The result follows.
$\blacksquare$
Sources
- 1933: D.M.Y. Sommerville: Analytical Conics (3rd ed.) ... (previous) ... (next): Chapter $\text {II}$. The Straight Line: $4$. Special forms of the equation of a straight line: $(3)$ Line through two points