Equivalence of Definitions of Boundary
Theorem
Let $T = \struct {S, \tau}$ be a topological space.
Let $H \subseteq S$.
The following definitions of the concept of boundary of $H$ are equivalent:
Definition $1$: from Closure and Interior
The boundary of $H$ consists of all the points in the closure of $H$ which are not in the interior of $H$.
Thus, the boundary of $H$ is defined as:
- $\partial H := H^- \setminus H^\circ$
where $H^-$ denotes the closure and $H^\circ$ the interior of $H$.
Definition $2$: from Neighborhood
$x \in S$ is a boundary point of $H$ if every neighborhood $N$ of $x$ satisfies:
- $H \cap N \ne \O$
and
- $\overline H \cap N \ne \O$
where $\overline H$ is the complement of $H$ in $S$.
The boundary of $H$ consists of all the boundary points of $H$.
Definition $3$: from Intersection of Closure with Closure of Complement
The boundary of $H$ is the intersection of the closure of $H$ with the closure of the complement of $H$ in $T$:
- $\partial H = H^- \cap \paren {\overline H}^-$
Definition $4$: from Closure and Exterior
The boundary of $H$ consists of all the points in $H$ which are not in either the interior or exterior of $H$.
Thus, the boundary of $H$ is defined as:
- $\partial H := H \setminus \paren {H^\circ \cup H^e}$
where:
Proof
Definition $1$ is equivalent to Definition $3$
This is demonstrated in Boundary is Intersection of Closure with Closure of Complement.
$\Box$
Definition $2$ is equivalent to Definition $3$
Let $x \in S$.
By definition of the closure:
- $x \in H^-$ if and only if every neighborhood $N$ of $x$ satisfies $H \cap N \ne \O$
- $x \in \paren{\overline H}^-$ if and only if every neighborhood $N$ of $x$ satisfies $\overline H \cap N \ne \O$
Therefore $x \in H^- \cap \paren{\overline H}^-$ if and only if every neighborhood $N$ of $x$ satisfies:
- $H \cap N \ne \O$
and
- $\overline H \cap N \ne \O$
$\Box$
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