Equivalent Sets have Equal Cardinal Numbers
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Theorem
Let $S$ and $T$ be sets.
Let $\card S$ denote the cardinal number of $S$.
Then:
- $S \sim T \implies \card S = \card T$
Proof
Let $x$ be an arbitrary set that is an ordinal:
\(\ds S\) | \(\sim\) | \(\ds T\) | by hypothesis | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds S \sim x\) | \(\iff\) | \(\ds T \sim x\) | Set Equivalence behaves like Equivalence Relation | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \set {x \in \On : S \sim x}\) | \(=\) | \(\ds \set {x \in \On : T \sim x}\) | Definition of Class Equality | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \bigcap \set {x \in \On : S \sim x}\) | \(=\) | \(\ds \bigcap \set {x \in \On : T \sim x}\) | Substitutivity of Class Equality | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \card S\) | \(=\) | \(\ds \card t\) | Definition of Cardinal Number |
$\blacksquare$
Sources
- 1971: Gaisi Takeuti and Wilson M. Zaring: Introduction to Axiomatic Set Theory: $\S 10.14$