Euclid's Theorem/Corollary 2/Proof 2
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Corollary to Euclid's Theorem
There is no largest prime number.
Proof
Aiming for a contradiction, suppose there exists a largest prime number $p$.
Let $b = p! + 1$.
Let $q$ be a prime number that divides $b$.
Since $p$ is the largest prime number, $q \le p$.
However, no positive integer $d \le p$ is a divisor of $b$.
Hence $q \not \le p$.
Hence the result, by Proof by Contradiction.
$\blacksquare$
Sources
- 1996: H. Jerome Keisler and Joel Robbin: Mathematical Logic and Computability ... (previous) ... (next): $\S 1.12$: Valid Arguments: Proposition $1.12.2$