Exchange of Order of Summations over Finite Sets/Cartesian Product/Proof 3
Jump to navigation
Jump to search
Theorem
Let $f: S \times T \to \mathbb A$ be a mapping.
Then we have an equality of summations over finite sets:
- $\ds \sum_{s \mathop \in S} \sum_{t \mathop \in T} \map f {s, t} = \sum_{t \mathop \in T} \sum_{s \mathop \in S} \map f {s, t}$
Proof
Let $n$ be the cardinality of $T$.
The proof goes by induction on $n$.
Basis for the Induction
Let $n = 0$.
![]() | This needs considerable tedious hard slog to complete it. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{Finish}} from the code.If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page. |
Induction Step
Let $n > 0$.
Let $t \in T$.
Use Cardinality of Set minus Singleton
![]() | This theorem requires a proof. You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by crafting such a proof. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{ProofWanted}} from the code.If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page. |