Exponential of a x by Cosine of b x and Exponential of a x by Sine of b x are Linearly Independent
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Theorem
Let $x, a, b \in \R$.
Then $e^{a x} \map \cos {b x}$ and $e^{b x} \map \sin {b x}$ are linearly independent.
Proof
Let $\alpha_1, \alpha_2 \in \R$ be such that:
- $\alpha_1 e^{a x} \map \cos {b x} + \alpha_2 e^{a x} \map \sin {b x} = 0$
Suppose $x = 0$.
Then $\alpha_1 = 0$.
Suppose $\ds x = \frac \pi {2 b}$.
Then:
- $\ds \alpha_2 \map \exp {\frac {\pi a} {2 b}} = 0$
Hence, $\alpha_2 = 0$.
The conclusion follows from the definition of linearly independent real functions.
$\blacksquare$
Sources
- 2017: Amol Sasane: A Friendly Approach to Functional Analysis ... (previous) ... (next): Chapter $\S 2.1$: Continuous and linear maps. Linear transformations