Exportation and Self-Conditional
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Theorem
- $p \land q \implies r \dashv \vdash \paren {p \implies q} \implies \paren {p \implies r}$
Proof
From the Rule of Exportation:
- $\paren {p \land q} \implies r \dashv \vdash p \implies \paren {q \implies r}$
Then by Self-Distributive Law for Conditional:
- $p \implies \paren {q \implies r} \dashv \vdash \paren {p \implies q} \implies \paren {p \implies r}$
$\blacksquare$