Fibonacci Number n+1 Minus Golden Mean by Fibonacci Number n/Proof 1

From ProofWiki
Jump to navigation Jump to search

Theorem

$F_{n + 1} - \phi F_n = \hat \phi^n$

where:

$F_n$ denotes the $n$th Fibonacci number
$\phi$ denotes the golden mean.


Proof

\(\ds F_{n + 1} - \phi F_n\) \(=\) \(\ds \dfrac 1 {\sqrt 5} \paren {\phi^{n + 1} - \hat \phi^{n + 1} } - \dfrac \phi {\sqrt 5} \paren {\phi^n - \hat \phi^n}\) Euler-Binet Formula
\(\ds \) \(=\) \(\ds \dfrac 1 {\sqrt 5} \paren {\phi^{n + 1} - \hat \phi^{n + 1} - \phi^{n + 1} + \phi \hat \phi^n}\)
\(\ds \) \(=\) \(\ds \hat \phi^n \dfrac {\phi - \hat \phi} {\sqrt 5}\)
\(\ds \) \(=\) \(\ds \hat \phi^n F_1\) Euler-Binet Formula
\(\ds \) \(=\) \(\ds \hat \phi^n\) Definition of Fibonacci Number: $F_1 = 1$

$\blacksquare$