Gamma Function Extends Factorial

From ProofWiki
Jump to navigation Jump to search

Theorem

$\forall n \in \N: \map \Gamma {n + 1} = n!$


Proof

For $n = 0$:

\(\ds \map \Gamma 1\) \(=\) \(\ds \int_0^\infty e^{-t} \rd t\) Definition of Gamma Function
\(\ds \) \(=\) \(\ds \bigintlimits {-e^{-t} } 0 \infty\)
\(\ds \) \(=\) \(\ds 0 - \paren {-1}\)
\(\ds \) \(=\) \(\ds 1\)


Then by Gamma Difference Equation:

$\forall z \in \Z_{> 0}: \map \Gamma {z + 1} = z \, \map \Gamma z$

Hence the result.

$\blacksquare$


Sources