Group Element Commutes with Inverse
Jump to navigation
Jump to search
Theorem
Let $\struct {G, \circ}$ be a group whose identity is $e$.
Let $x \in G$.
Then:
- $x \circ x^{-1} = x^{-1} \circ x$
That is, $x$ commutes with its inverse $x^{-1}$.
Proof
By definition of inverse element:
- $x \circ x^{-1} = e = x^{-1} \circ x$
Hence the result by definition.
Sources
- 1964: Walter Ledermann: Introduction to the Theory of Finite Groups (5th ed.) ... (previous) ... (next): Chapter $\text {I}$: The Group Concept: $\S 2$: The Axioms of Group Theory
- 1965: J.A. Green: Sets and Groups ... (previous) ... (next): $\S 4.6$. Elementary theorems on groups: Example $86$