Group Homomorphism/Examples/Pointwise Addition on Continuous Real Functions on Closed Unit Interval/Example 1

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Example of Group Homomorphism

Let $J \subseteq \R$ denote the closed unit interval $\closedint 0 1$.

Let $\map {\mathscr C} J$ denote the set of all continuous real functions from $J$ to $\R$.

Let $G = \struct {\map {\mathscr C} J, +}$ be the group formed on $\map {\mathscr C} J$ by pointwise addition.

Let $\struct {\R, +}$ denote the additive group of real numbers.


From Pointwise Addition on Continuous Real Functions on Closed Unit Interval forms Group we have that $G$ is indeed a group.


Let $\phi: \struct {\map {\mathscr C} J, +} \to \struct {\R, +}$ be the mapping defined as:

$\forall f \in \map {\mathscr C} J: \map \phi f = \map f 1$

Then $\phi$ is a homomorphism.


Kernel

The kernel of $\phi$ is given by:

$\map \ker \phi = I_J - f_m$

where:

$f_m: \R \to \R$ denotes the constant mapping on $\R$
$m = 1$
$I_J$ denotes the identity mapping on $J$.


Proof

Let $f, g \in \map {\mathscr C} J$ be arbitrary.

We have:

\(\ds \map \phi {f + g}\) \(=\) \(\ds \map {\paren {f + g} } 1\) Definition of $\phi$
\(\ds \) \(=\) \(\ds \map f 1 + \map g 1\) Definition of Pointwise Addition of Real-Valued Functions
\(\ds \) \(=\) \(\ds \map \phi f + \map \phi g\)

Thus $\phi$ is a homomorphism by definition.

$\blacksquare$


Sources

  • 1965: Seth Warner: Modern Algebra ... (previous) ... (next): Chapter $\text {II}$: New Structures from Old: $\S 13$: Compositions Induced on Cartesian Products and Function Spaces: Exercise $13.18 \ \text {(a)}$