Henry Ernest Dudeney/Puzzles and Curious Problems/163 - Domino Fractions/Solution
Jump to navigation
Jump to search
Puzzles and Curious Problems by Henry Ernest Dudeney: $163$
- Domino Fractions
- Taking an ordinary box, discard all doubles and blanks.
- Then, substituting figures for the pips, regard the remaining $15$ dominoes as fractions.
Solution
This gives us the equations:
\(\ds \dfrac 1 3 + \dfrac 6 1 + \dfrac 3 4 + \dfrac 5 3 + \dfrac 5 4\) | \(=\) | \(\ds \dfrac {4 + 72 + 9 + 20 + 15} {12}\) | \(\ds = \dfrac {120} {12} = 10\) | |||||||||||
\(\ds \dfrac 2 1 + \dfrac 5 1 + \dfrac 2 6 + \dfrac 6 3 + \dfrac 4 6\) | \(=\) | \(\ds \dfrac {12 + 30 + 2 + 12 + 4} 6\) | \(\ds = \dfrac {60} 6 = 10\) | |||||||||||
\(\ds \dfrac 4 1 + \dfrac 2 3 + \dfrac 4 2 + \dfrac 5 2 + \dfrac 5 6\) | \(=\) | \(\ds \dfrac {24 + 4 + 12 + 15 + 5} 6\) | \(\ds = \dfrac {60} 6 = 10\) |
Sources
- 1932: Henry Ernest Dudeney: Puzzles and Curious Problems ... (previous) ... (next): Solutions: $163$. -- Domino Fractions
- 1968: Henry Ernest Dudeney: 536 Puzzles & Curious Problems ... (previous) ... (next): Answers: $480$. Domino Fractions