# Homomorphism with Cancellable Codomain Preserves Identity

## Theorem

Let $\struct {S, \circ}$ and $\struct {T, *}$ be algebraic structures.

Let $\phi: \struct {S, \circ} \to \struct {T, *}$ be a homomorphism.

Let $\struct {S, \circ}$ have an identity $e_S$.

Let $\struct {T, *}$ have an identity $e_T$.

Let every element of $\struct {T, *}$ be cancellable.

Then $\map \phi {e_S}$ is the identity $e_T$.

## Proof

Let $\struct {S, \circ}$ be an algebraic structure in which $\circ$ has an identity $e_S$.

Let $\struct {T, *}$ be an algebraic structure in which $*$ has an identity $e_T$.

Let $\struct {T, *}$ be such that every element is cancellable.

Let $\phi: \struct {S, \circ} \to \struct {T, *}$ be a homomorphism.

Every element of $\struct {T, *}$ is cancellable.

Suppose there is an idempotent element in $\struct {T, *}$

So from Identity is only Idempotent Cancellable Element, it must be the identity $e_T$.

Thus:

 $\ds \map \phi {e_S} * \map \phi {e_S}$ $=$ $\ds \map \phi {e_S \circ e_S}$ Definition of Morphism Property $\ds$ $=$ $\ds \map \phi {e_S}$ Definition of Identity Element

So $\map \phi {e_S}$ is idempotent in $\struct {T, *}$ and the result follows.

$\blacksquare$