Integer Divisor Results
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Theorem
Let $m, n \in \Z$ be integers.
Let $m \divides n$ denote that $m$ is a divisor of $n$.
The following results all hold:
One Divides all Integers
\(\ds 1\) | \(\divides\) | \(\ds n\) | ||||||||||||
\(\ds -1\) | \(\divides\) | \(\ds n\) |
Integer Divides Itself
- $n \divides n$
Integer Divides its Negative
\(\ds n\) | \(\divides\) | \(\ds -n\) | ||||||||||||
\(\ds -n\) | \(\divides\) | \(\ds n\) |
Integer Divides its Absolute Value
\(\ds n\) | \(\divides\) | \(\ds \size n\) | ||||||||||||
\(\ds \size n\) | \(\divides\) | \(\ds n\) |
where:
- $\size n$ is the absolute value of $n$
- $\divides$ denotes divisibility.
Integer Divides Zero
- $n \divides 0$
Divisors of Negative Values
- $m \divides n \iff -m \divides n \iff m \divides -n \iff -m \divides -n$