Integral of Increasing Function Composed with Measurable Function
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Theorem
Let $\struct {X, \Sigma, \mu}$ be a $\sigma$-finite measure space.
Let $f: X \to \R_{\ge 0}$ be a positive measurable function.
Let $\phi: \R_{\ge 0} \to \R_{\ge 0}$ be a continuously differentiable, increasing function such that $\map \phi 0 = 0$.
Then:
- $\ds \int \phi \circ f \rd \mu = \int_0^\infty \map {\phi'} t \map F t \rd t$
where:
- $F$ is the survival function of $f$
- $\ds \int_0^\infty$ denotes an improper integral.
Corollary
Let $f: X \to \R$ be a $p$-integrable function.
Then:
- $\ds \norm f_p^p = \int_0^\infty p t^{p - 1} \map F t \rd t$
where $F$ is the survival function of $\size f$.
Proof
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Sources
- 2005: René L. Schilling: Measures, Integrals and Martingales ... (previous) ... (next): $13.13$
- 2014: Loukas Grafakos: Classical Fourier Analysis (3rd ed.) ... (previous) ... (next): $1.1.1$: The Distribution Function