Integration by Substitution/Examples/(2x + 3) by Root of x^2 + 3x + 2
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Example of Use of Integration by Substitution
- $\ds \int \paren {2 x + 3} \sqrt {x^2 + 3 x + 2} \rd x = \dfrac 2 3 {\paren {\sqrt {x^2 + 3 x + 2} }^3} + C$
Proof
\(\ds u\) | \(=\) | \(\ds x^2 + 3 x + 2\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \frac {\d u} {\d x}\) | \(=\) | \(\ds 2 x + 3\) | Power Rule for Derivatives | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \int \paren {2 x + 3} \sqrt {x^2 + 3 x + 2} \rd x\) | \(=\) | \(\ds \int \sqrt u \rd u\) | Primitive of Composite Function: Corollary | ||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {2 u^{3/2} } 3 + C\) | Primitive of Square Root | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac 2 3 {\paren {\sqrt {x^2 + 3 x + 2} }^3} + C\) | substituting for $u$ and simplifying |
$\blacksquare$
Sources
- 1953: L. Harwood Clarke: A Note Book in Pure Mathematics ... (previous) ... (next): $\text {II}$. Calculus: Exercises $\text {XIV}$: $6$.