Intersection Distributes over Union/Examples/Arbitrary Integer Sets
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Example of Use of Intersection Distributes over Union
Let:
\(\ds A\) | \(=\) | \(\ds \set {2, 4, 6, 8, \dotsc}\) | ||||||||||||
\(\ds B\) | \(=\) | \(\ds \set {1, 3, 5, 7, \dotsc}\) | ||||||||||||
\(\ds C\) | \(=\) | \(\ds \set {1, 2, 3, 4}\) |
Then:
- $\paren {A \cup B} \cap C = \set {1, 2, 3, 4} = \paren {A \cap C} \cup \paren {B \cap C}$
Proof
\(\ds \paren {A \cup B} \cap C\) | \(=\) | \(\ds \paren {\set {2, 4, 6, 8, \dotsc} \cup \set {1, 3, 5, 7, \dotsc} } \cap \set {1, 2, 3, 4}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \set {1, 2, 3, 4, 5, 6, 7, 8, \dotsc} \cap \set {1, 2, 3, 4}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \set {1, 2, 3, 4}\) |
\(\ds \paren {A \cap C} \cup \paren {B \cap C}\) | \(=\) | \(\ds \paren {\set {2, 4, 6, 8, \dotsc} \cap \set {1, 2, 3, 4} } \cup \paren {\set {1, 3, 5, 7, \dotsc} \cap \set {1, 2, 3, 4} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \set {2, 4} \cup \set {1, 3}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \set {1, 2, 3, 4}\) |
$\blacksquare$
Sources
- 1975: T.S. Blyth: Set Theory and Abstract Algebra ... (previous) ... (next): $\S 1$. Sets; inclusion; intersection; union; complementation; number systems: Exercise $1$