Intersection of Family/Examples/Size of y-1 lt n and Size of y+1 gt 1 over n
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Example of Intersection of Family
Let $I$ be the indexing set $I = \set {1, 2, 3, \ldots}$
Let $\family {T_n}$ be the indexed family of subsets of the set of real numbers $\R$, defined as:
- $T_n = \set {y: \size {y - 1} < n \land \size {y + 1} > \dfrac 1 n}$
Then:
- $\ds \bigcap_{n \mathop \in I} T_n = \openint 0 2$
Proof
From Size of y-1 lt n and Size of y+1 gt 1 over n:
- $T_n = \openint {1 - n} {-1 - \dfrac 1 n} \cup \openint {-1 + \dfrac 1 n} {1 + n}$
We have that:
- $\paren {\openint {1 - n} {-1 - \dfrac 1 n} \cup \openint {-1 + \dfrac 1 n} {1 + n} } \subseteq \paren {\openint {1 - \paren {n + 1} } {-1 - \dfrac 1 {n + 1} } \cup \openint {-1 + \dfrac 1 {n + 1} } {1 + \paren {n + 1} } }$
That is:
- $T_n \subseteq T_{n + 1}$
and so:
- $\ds \bigcap_{n \mathop \in I} T_n = T_1$
Hence:
\(\ds \bigcap_{n \mathop \in I} T_n\) | \(=\) | \(\ds T_1\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \openint {1 - 1} {-1 - \dfrac 1 1} \cup \openint {-1 + \dfrac 1 1} {1 + 1}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \openint 0 {-2} \cup \openint 0 2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \O \cup \openint 0 2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \openint 0 2\) |
$\blacksquare$
Sources
- 1967: George McCarty: Topology: An Introduction with Application to Topological Groups ... (previous) ... (next): Chapter $\text{I}$: Sets and Functions: Exercise $\text {A}$