# Inverse of Injection is Many-to-One Relation

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## Theorem

Let $f: S \to T$ be an injection.

Let $f^{-1}: T \to S$ be the inverse relation of $f$.

Then $f^{-1}$ is many-to-one.

## Proof

Let $f: S \to T$ be an injection.

We have by definition of inverse relation that:

- $f^{-1} = \set {\tuple {t, s}: t = \map f s}$

Let $f: S \to T$ be an injection.

Let $\tuple {t, s_1} \in f^{-1}$ and $\tuple {t, s_2} \in f^{-1}$.

By definition, we have that $\map f {s_1} = t = \map f {s_2}$.

But as $f$ is an injection:

- $\map f {s_1} = \map f {s_2} \implies s_1 = s_2$

So we have that:

- $\tuple {t, s_1} \in f^{-1} \land \tuple {t, s_2} \in f^{-1} \implies s_1 = s_2$

and so by definition, $f^{-1}$ is a many-to-one relation.

$\blacksquare$