Like Electric Charges Repel
Theorem
Let $a$ and $b$ be stationary particles, each carrying an electric charge of $q_a$ and $q_b$ respectively.
Let $q_a$ and $q_b$ be of the same polarity.
That is, let $q_a$ and $q_b$ be like charges.
Then the forces exerted by $a$ on $b$, and by $b$ on $a$, are such as to cause $a$ and $b$ to repel each other.
Proof
By Coulomb's Law of Electrostatics:
- $\mathbf F_{a b} \propto \dfrac {q_a q_b {\mathbf r_{a b} } } {r^3}$
where:
- $\mathbf F_{a b}$ is the force exerted on $b$ by the electric charge on $a$
- $\mathbf r_{a b}$ is the displacement vector from $a$ to $b$
- $r$ is the distance between $a$ and $b$.
Let $q_a$ and $q_b$ both be positive.
Then $q_a q_b$ is a positive number multiplied by a positive number.
Thus $q_a q_b$ is a positive number.
Similarly, let $q_a$ and $q_b$ both be negative.
Then $q_a q_b$ is a negative number multiplied by a negative number.
Thus $q_a q_b$ is similarly a positive number.
So, when $q_a$ and $q_b$ are like charges, $\dfrac {q_a q_b} {r^3}$ is a positive number.
Hence $\mathbf F_{a b}$ is in the same direction as the displacement vector from $a$ to $b$.
That is, the force exerted on $b$ by the electric charge on $a$ is in the direction away from $a$.
The same applies to the force exerted on $a$ by the electric charge on $b$.
That is, the force exerted on $b$ by the electric charge on $a$ is in the direction away from $b$.
The effect of these forces is to cause $a$ and $b$ to push apart, that is, to repel each other.
Also see
Sources
- 1958: C.A. Coulson: Electricity (5th ed.) ... (previous) ... (next): Chapter $\text {I}$: Preliminary Survey: $\S 1$. Electrostatics
- 1990: I.S. Grant and W.R. Phillips: Electromagnetism (2nd ed.) ... (previous) ... (next): Chapter $1$: Force and energy in electrostatics: $1.1$ Electric Charge