Lower Closure is Increasing

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Theorem

Let $\struct {S, \preceq}$ be an ordered set.

Let $x, y$ be elements of $S$ such that

$x \preceq y$


Then:

$x^\preceq \subseteq y^\preceq$

where $y^\preceq$ denotes the lower closure of $y$.


Proof

Let $z \in x^\preceq$.

By definition of lower closure of element:

$z \preceq x$

By definition of transitivity:

$z \preceq y$

Thus again by definition of lower closure of element:

$z \in y^\preceq$

$\blacksquare$


Sources