Magic Constant of Order 3 Magic Square/Proof 1
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Theorem
The magic constant of the order $3$ magic square is $15$.
Proof
Let $M_3$ denote the order $3$ magic square
By Sum of Terms of Magic Square, the total of all the entries in $M_3$ is given by:
- $T_3 = \dfrac {3^2 \left({3^2 + 1}\right)} 2 = \dfrac {9 \times 10} 2 = 45$
As there are $3$ rows of $M_3$, the magic constant of $M_3$ is given by:
- $S_3 = \dfrac {45} 3 = 15$
$\blacksquare$