Modulus of Limit/Normed Division Ring

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Theorem

Let $\struct {R, \norm {\, \cdot \,} }$ be a normed division ring.

Let $\sequence {x_n}$ be a convergent sequence in $R$ to the limit $l$.

That is, let $\ds \lim_{n \mathop \to \infty} x_n = l$.


Then

$\ds \lim_{n \mathop \to \infty} \norm {x_n} = \norm l$

where $\sequence {\norm {x_n} }$ is a real sequence.


Proof

By the Reverse Triangle Inequality, we have:

$\cmod {\norm {x_n} - \norm l} \le \norm {x_n - l}$

Hence by the Squeeze Theorem and Convergent Sequence Minus Limit, $\norm {x_n} \to \norm l$ as $n \to \infty$.

$\blacksquare$


Sources