Modulus z - 1 Less than Modulus z + 1 iff Real z Greater than Zero
Jump to navigation
Jump to search
Theorem
Let $z \in \C$ be a complex number.
Then:
- $\cmod {z - 1} < \cmod {z + 1} \iff \map \Re z > 0$
Proof
\(\ds \cmod {z - 1}\) | \(<\) | \(\ds \cmod {z + 1}\) | ||||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \cmod {z + 1}\) | \(>\) | \(\ds \cmod {z - 1}\) | |||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \paren {x + 1}^2 + y^2\) | \(>\) | \(\ds \paren {x - 1}^2 + y^2\) | Definition of Complex Modulus | ||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \paren {x + 1}^2\) | \(>\) | \(\ds \paren {x - 1}^2\) | |||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds x^2 + 2 x + 1\) | \(>\) | \(\ds x^2 - 2 x + 1\) | |||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds 4 x\) | \(>\) | \(\ds 0\) | |||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds x\) | \(>\) | \(\ds 0\) | |||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \Re z\) | \(>\) | \(\ds 0\) | Definition of Real Part |
$\blacksquare$
Sources
- 1981: Murray R. Spiegel: Theory and Problems of Complex Variables (SI ed.) ... (previous) ... (next): $1$: Complex Numbers: Supplementary Problems: Miscellaneous Problems: $144$