Norm on Bounded Linear Functional is Finite
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Theorem
Let $V$ be a normed vector space.
Let $L$ be a bounded linear functional on $V$.
Let $\norm L$ denote the norm on $L$ defined as:
- $\norm L = \inf \set {c > 0: \forall v \in V: \size {L v} \le c \norm v_V}$
Then:
- $\norm L < \infty$
Proof
By definition of a bounded linear functional:
- $\exists c \in \R_{> 0}: \forall v \in V: \size{L v} \le c \norm v_V$
Hence:
- $\set {\lambda > 0: \forall v \in V: \size {L v} \le \lambda \norm v_V} \ne \O$
By definition:
$\set {\lambda > 0: \forall v \in V: \size {L v} \le \lambda \norm v_V}$ is bounded below by $0$.
From the Greatest Lower Bound Property:
- $\norm L = \inf \set {\lambda > 0: \forall v \in V: \size {L v} \le \lambda \norm v_V}$ exists.
We have:
\(\ds \norm L\) | \(\le\) | \(\ds c\) | Definition of Infimum | |||||||||||
\(\ds \) | \(<\) | \(\ds \infty\) | because $c \in \R_{>0}$ |
The result follows.
$\blacksquare$