Number divides Number iff Square divides Square
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Theorem
Let $a, b \in \Z$.
Then:
- $a^2 \divides b^2 \iff a \divides b$
where $\divides$ denotes integer divisibility.
In the words of Euclid:
- If a square measure a square, the side will also measure the side; and, if the side measure the side, the square will also measure the square.
(The Elements: Book $\text{VIII}$: Proposition $14$)
Proof
From Between two Squares exists one Mean Proportional:
- $\tuple {a^2, ab, b^2}$
is a geometric sequence.
Let $a, b \in \Z$ such that $a^2 \divides b^2$.
Then from First Element of Geometric Sequence that divides Last also divides Second:
- $a^2 \divides a b$
Thus:
\(\ds a^2\) | \(\divides\) | \(\ds a b\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \exists k \in \Z: \, \) | \(\ds k a^2\) | \(=\) | \(\ds a b\) | Definition of Divisor of Integer | |||||||||
\(\ds \leadsto \ \ \) | \(\ds k a\) | \(=\) | \(\ds b\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds a\) | \(\divides\) | \(\ds b\) | Definition of Divisor of Integer |
$\Box$
Let $a \divides b$.
Then:
\(\ds a\) | \(\divides\) | \(\ds b\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \exists k \in \Z: \, \) | \(\ds k a\) | \(=\) | \(\ds b\) | Definition of Divisor of Integer | |||||||||
\(\ds \leadsto \ \ \) | \(\ds k a^2\) | \(=\) | \(\ds a b\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds k a b\) | \(=\) | \(\ds b^2\) | Definition of Geometric Sequence of Integers | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds k^2 a^2\) | \(=\) | \(\ds b^2\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds a^2\) | \(\divides\) | \(\ds b^2\) | Definition of Divisor of Integer |
$\blacksquare$
Historical Note
This proof is Proposition $14$ of Book $\text{VIII}$ of Euclid's The Elements.
Sources
- 1926: Sir Thomas L. Heath: Euclid: The Thirteen Books of The Elements: Volume 2 (2nd ed.) ... (previous) ... (next): Book $\text{VIII}$. Propositions