Number of Non-Dividing Primes Less than n is Less than Euler Phi Function of n
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Theorem
Let $n \in \Z_{>0}$ be a strictly positive integer.
Let $\map w n$ denote the number of primes strictly less than $n$ which are not divisors of $n$.
Let $\map \phi n$ denote the Euler $\phi$ function of $n$.
Then:
- $\map w n < \map \phi n$
Proof
Let $P = \set {p < n: p \text { prime}, p \nmid n}$.
Let $Q = \set {0 < q < n: q \perp n}$, where $q \perp n$ denotes that $q$ and $n$ are coprime.
Let $p \in P$.
From Prime not Divisor implies Coprime, $p$ is coprime to $n$.
That is:
- $p \in Q$
So, by definition of subset:
- $P \subseteq Q$
From Integer is Coprime to 1:
- $1 \in Q$
But as One is not Prime:
- $1 \notin P$
Thus $P \subsetneq Q$ and so:
- $\card P < \card Q$
By definition of $\map w n$:
- $\card P = \map w n$
and by definition of Euler $\phi$ function:
- $\card Q = \map \phi n$
Hence the result.
$\blacksquare$
Sources
- 1971: George E. Andrews: Number Theory ... (previous) ... (next): $\text {4-2}$ Residue Systems: Exercise $4$