Open Unit Interval is Proper Subset of Closed Unit Interval
Jump to navigation
Jump to search
Theorem
The open unit interval:
- $I_o = \openint 0 1$
is a proper subset of the closed unit interval:
- $I_c = \closedint 0 1$
Proof
Let $x \in I_o$.
Then by definition:
- $0 < x < 1$
and so:
- $0 \le x \le 1$
and so:
- $x \in I_c$.
Thus:
- $I_o \subseteq I_c$
Consider:
- $0 \in I_c$
by definition of closed interval.
But it is not the case that $0 < 0$.
So $0 \notin I_o$ and so $I_c \nsubseteq I_o$.
Hence the result by definition of proper subset.
$\blacksquare$
Sources
- 1964: William K. Smith: Limits and Continuity ... (previous) ... (next): $\S 2.1$: Sets