Ordering on Cuts is Compatible with Addition of Cuts/Corollary

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Theorem

Let $\alpha$ and $\gamma$ be cuts.

Let the operation of $\alpha + \gamma$ be the sum of $\alpha$ and $\gamma$.

Let $0^*$ denote the rational cut associated with the (rational) number $0$.


If:

$\alpha > 0^*$ and $\gamma > 0^*$

then:

$\alpha + \gamma > 0^*$

where $>$ denotes the strict ordering on cuts.


Proof

From Ordering on Cuts is Compatible with Addition of Cuts

$0^* + 0^* < 0^* + \alpha$
$\alpha + 0^* < \alpha + \gamma$

The result follows from Ordering on Cuts is Transitive.

$\blacksquare$


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