Positive Rational Numbers under Addition form Commutative Monoid

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $\Q_{\ge 0}$ denote the set of positive rational numbers.

The algebraic structure:

$\struct {\Q_{\ge 0}, +}$

forms a commutative monoid.


Proof

From Rational Numbers form Field, $\struct {\Q, +, \times}$ is a field.

Hence $\struct {\Q, +}$ is an abelian group.


From Positive Rational Numbers are Closed under Addition we have that $\struct {\Q_{\ge 0}, +}$ is closed.

Hence from Subsemigroup Closure Test, $\struct {\Q_{\ge 0}, +}$ is a subsemigroup of $\struct {\Q, +}$.


From Restriction of Commutative Operation is Commutative, $\struct {\Q_{\ge 0}, +}$ is a commutative semigroup.


We have that $0$ is the identity element of $\struct {\Q, +}$.

Hence from Identity of Subsemigroup of Group, $0$ is also the identity element of $\struct {\Q_{\ge 0}, +}$.


So $\struct {\Q_{\ge 0}, +}$ is a commutative monoid.

$\blacksquare$