Prime Number divides Infinite Number of Fibonacci Numbers

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Theorem

Let $p$ be a prime number.

Then there exist an infinite number of Fibonacci numbers which are divisible by $p$.


Proof

From Prime Number divides Fibonacci Number, either $F_{p - 1}$ or $F_{p + 1}$ is divisible by $p$.

Thus:

\(\ds p\) \(\divides\) \(\ds F_{p \pm 1}\) Prime Number divides Fibonacci Number
\(\ds \forall n \in \Z_{>0}: \, \) \(\ds F_{p \pm 1}\) \(\divides\) \(\ds F_{n \paren {p \pm 1} }\) Divisibility of Fibonacci Number
\(\ds \leadsto \ \ \) \(\ds \forall n \in \Z_{>0}: \, \) \(\ds p\) \(\divides\) \(\ds F_{n \paren {p \pm 1} }\)

$\blacksquare$


Sources