Primitive of Reciprocal of Root of x squared plus a squared/Logarithm Form/Also presented as
Jump to navigation
Jump to search
Primitive of $\frac 1 {\sqrt {x^2 + a^2} }$: Logarithm Form: Also presented as
The standard presentation of this result is:
- $\ds \int \frac {\d x} {\sqrt {x^2 + a^2} } = \map \ln {x + \sqrt {x^2 + a^2} } + C$
Some sources present this in the form:
- $\ds \int \frac {\d x} {\sqrt {x^2 + a^2} } = \map \ln {\dfrac {x + \sqrt {x^2 + a^2} } a} + C$
which is the same as above, except that the constant $a$ has not been subsumed into the arbitrary constant $C$.
Some sources present it as:
- $\ds \int \frac {\d x} {\sqrt {x^2 + a^2} } = \ln \size {x + \sqrt {x^2 + a^2} } + C$
Sources
- 1945: A. Geary, H.V. Lowry and H.A. Hayden: Advanced Mathematics for Technical Students, Part I ... (previous) ... (next): Chapter $\text {III}$: Integration: Integration
- 1960: Margaret M. Gow: A Course in Pure Mathematics ... (previous) ... (next): Chapter $10$: Integration: $10.4$. Standard integrals: Standard Forms: $\text {(x)}$
- 1968: George B. Thomas, Jr.: Calculus and Analytic Geometry (4th ed.) ... (previous) ... (next): Front endpapers: A Brief Table of Integrals: $20$.