Primitive of Reciprocal of x by square of a x squared plus b x plus c
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Theorem
Let $a \in \R_{\ne 0}$.
Then:
- $\ds \int \frac {\d x} {x \paren {a x^2 + b x + c}^2} = \frac 1 {2 c \paren {a x^2 + b x + c} } - \frac b {2 c} \int \frac {\d x} {\paren {a x^2 + b x + c}^2} + \frac 1 c \int \frac {\d x} {x \paren {a x^2 + b x + c} }$
Proof
\(\ds \int \frac {\d x} {x \paren {a x^2 + b x + c}^2}\) | \(=\) | \(\ds \int \frac {c \rd x} {c x \paren {a x^2 + b x + c}^2}\) | multiplying top and bottom by $c$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 c \int \frac {c \rd x} {x \paren {a x^2 + b x + c}^2}\) | Primitive of Constant Multiple of Function | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 c \int \frac {a x^2 + b x + c - a x^2 - b x} {x \paren {a x^2 + b x + c}^2} \rd x\) | adding and subtracting $a x^2 + b x$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 c \int \frac {\paren {a x^2 + b x + c} \rd x} {x \paren {a x^2 + b x + c}^2} - \frac a c \int \frac {x^2 \rd x} {x \paren {a x^2 + b x + c}^2}\) | Linear Combination of Primitives | |||||||||||
\(\ds \) | \(\) | \(\, \ds - \, \) | \(\ds \frac b c \int \frac {x \rd x} {x \paren {a x^2 + b x + c}^2}\) | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 c \int \frac {\d x} {x \paren {a x^2 + b x + c} } - \frac a c \int \frac {x \rd x} {\paren {a x^2 + b x + c}^2}\) | simplification | |||||||||||
\(\ds \) | \(\) | \(\, \ds - \, \) | \(\ds \frac b c \int \frac {\d x} {\paren {a x^2 + b x + c}^2}\) | |||||||||||
\(\ds \) | \(=\) | \(\ds -\frac {2 a} {2 c} \int \frac {x \rd x} {\paren {a x^2 + b x + c}^2} - \frac b {2 c} \int \frac {\d x} {\paren {a x^2 + b x + c}^2}\) | splitting up the $\dfrac b c$ term | |||||||||||
\(\ds \) | \(\) | \(\, \ds - \, \) | \(\ds \frac b {2 c} \int \frac {\d x} {\paren {a x^2 + b x + c}^2} + \frac 1 c \int \frac {\d x} {x \paren {a x^2 + b x + c} }\) | |||||||||||
\(\ds \) | \(=\) | \(\ds -\frac 1 {2 c} \int \frac {\paren {2 a x + b} \rd x} {\paren {a x^2 + b x + c}^2}\) | Linear Combination of Primitives | |||||||||||
\(\ds \) | \(\) | \(\, \ds - \, \) | \(\ds \frac b {2 c} \int \frac {\d x} {\paren {a x^2 + b x + c}^2} + \frac 1 c \int \frac {\d x} {x \paren {a x^2 + b x + c} }\) | |||||||||||
\(\ds \) | \(=\) | \(\ds -\frac 1 {2 c} \paren {\frac {-1} {a x^2 + b x + c} }\) | Primitive of Function under its Derivative | |||||||||||
\(\ds \) | \(\) | \(\, \ds - \, \) | \(\ds \frac b {2 c} \int \frac {\d x} {\paren {a x^2 + b x + c}^2} + \frac 1 c \int \frac {\d x} {x \paren {a x^2 + b x + c} }\) | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 {2 c \paren {a x^2 + b x + c} }\) | simplifying | |||||||||||
\(\ds \) | \(\) | \(\, \ds - \, \) | \(\ds \frac b {2 c} \int \frac {\d x} {\paren {a x^2 + b x + c}^2} + \frac 1 c \int \frac {\d x} {x \paren {a x^2 + b x + c} }\) |
$\blacksquare$
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 14$: Integrals involving $a x^2 + b x + c$: $14.277$