Primitive of x by Cosine of x/Proof 3
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Theorem
- $\ds \int x \cos x \rd x = \cos x + x \sin x + C$
Proof
We have:
\(\ds \map {\dfrac \d {\d x} } {\cos x + x \sin x}\) | \(=\) | \(\ds \map {\dfrac \d {\d x} } {\cos x} + \map {\dfrac \d {\d x} } {x \sin x}\) | Sum Rule for Derivatives | |||||||||||
\(\ds \) | \(=\) | \(\ds \map {\dfrac \d {\d x} } {\cos x} + x \map {\dfrac \d {\d x} } {\sin x} + \map {\dfrac \d {\d x} } x \sin x\) | Product Rule for Derivatives | |||||||||||
\(\ds \) | \(=\) | \(\ds -\sin x + x \cos x + \sin x\) | Derivative of Cosine Function, Derivative of Sine Function, Derivative of Identity Function | |||||||||||
\(\ds \) | \(=\) | \(\ds x \cos x\) | simplifying |
Hence the result by definition of primitive.
$\blacksquare$
Sources
- 1945: A. Geary, H.V. Lowry and H.A. Hayden: Advanced Mathematics for Technical Students, Part I ... (previous) ... (next): Chapter $\text {III}$: Integration: Three rules for integration: $\text {I}$