Product of Number of Edges, Edges per Face and Faces of Tetrahedron

From ProofWiki
Jump to navigation Jump to search

Theorem

The product of the number of edges, edges per face and faces of a tetrahedron is $72$.


Proof

A tetrahedron has:

$6$ edges

and:

$4$ faces.

Each face is a triangle, and so has $3$ edges.

Hence:

$6 \times 4 \times 3 = 72$

$\blacksquare$


Sources