Product of Two Distinct Primes is Multiplicatively Perfect
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Theorem
Let $n \in \Z_{>0}$ be a positive integer which is the product of $2$ distinct primes.
Then $n$ is multiplicatively perfect.
Proof
Let $n = p \times q$ where $p$ and $q$ are primes.
From Product of Two Distinct Primes has 4 Positive Divisors, the positive divisors of $n$ are:
- $1, p, q, pq$
Thus the product of all the divisors of $n$ is:
- $1 \times p \times q \times p q = p^2 q^2 = n^2$
Hence the result, by definition of multiplicatively perfect.
$\blacksquare$
Sources
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $33$